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Set 56 Problem number 2


Problem

Observation of a passing wave shows that its frequency is 20 cycles/sec, and that the wave travels at 100 meters/second.  What therefore is the wavelength of the wave?

Solution

If 20 peaks pass in a second, then the section of the wave that passes in a second must contain 20 peaks.

Since the wave travels at 100 meters/second, the section of the wave that passes in a second must be 100 meters long.

Therefore there are 20 peaks in 100 meters.

The distance between peaks must therefore be

We call this distance between peaks the wavelength of the wave.

Generalized Solution

If f peaks per second pass at velocity v, then in time interval `dt, the number of peaks will be f `dt and the distance moved will be v `dt.

If there are f `dt peaks spread over distance v `dt, then the distance between peaks is v `dt / f `dt = v / f.

Explanation in terms of Figure(s), Extension

The figure below depicts the segment of the wave that will pass in time interval `dt. This segment has length v `dt. Since its frequency is f, which represents the number of peaks passing per unit of time, we also seen that the number of peaks is f `dt.

The distance between peaks is easily found by dividing the number of peaks into the distance over which they are spread. In this case the distance is

This distance is called the wavelength of the wave.

Figure(s)

wavelength_from_frequency_and_velocity.gif (8856 bytes)

 

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